
Are you a match for the Logic Fiend?!!
The challenge of the 12 eggs The chamber of 9 doors The challenge of the 9 eggs The 5 protistas on the run The 4 protistas on the run Shakeel's Fiendish Illusion You lucky muskrats. I'm amazed! I hope you are ready. THIS IS AN OUTRAGE Friday the 13th Three naked logical fiends, and yourself. the selfish, logical protistas a teaser.  The challenge of the 12 eggs Saturday, October 21, 2006 Well, well, well... your brains have fermented long enough! It is time for round two of the challenge of the eggs! MuHaHAHAHAa!!! ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ To the logic fiend, it's a widely known fact that the South Uruguayan cockatoo only lays eggs that are 12 oz. Well, actually there is an exception. If a cockatoo lays an egg on the night of a full moon, the egg will deviate slightly from the 12 oz. norm. A logic fiend gives you 12 eggs  11 are 12 oz., but 1 is not. The logic fiends also gives you a very accurate balance and tells you to determine the odd egg out with only 3 uses of the balance. Here is a picture of the balance. How do you do it? Each unique solution will earn you 100 pps. Comment! (4)  Recommend! (2)  Categories: brain teaser [t], logic puzzle [t] The chamber of 9 doors Saturday, September 10, 2005 A treasure map that leads to a medieval castle is found. The location of the treasure is indicated to be in a chamber with 9 doors leading to 9 different rooms. Of the 9 doors, only the last 8 are locked. The doors are evenly spread apart and naturally numbered starting with nonnegative integers in a consecutive order. The map indicates that the treasure is behind an even numbered door with an equal number of doors on each side. As a bonus, there are two chests with an additional 5,000 gold pieces each. The chests are separately located behind two doors farthest from the treasure on each side. The wood gnome Bob is the magical guardian of the treasures. In order for him to give you the keys which unlock the correct doors; you must tell him the roman numerals for the doors that lead to the treasures as well as the reasoning for not locking one of the doors. Comment! (5)  Recommend! The challenge of the 9 eggs Saturday, July 30, 2005 To the logic fiend, it's a widely known fact that the South Uruguayan cockatoo only lays eggs that are 12 oz. Well, actually there is an exception. If a cockatoo lays an egg on the night of a full moon, the egg will deviate slightly from the 12 oz. norm. A logic fiend gives you 9 eggs  8 are 12 oz., but 1 is not. The logic fiends also gives you a very accurate balance and tells you to determine the odd egg out with only 3 uses of the balance. Here is a picture of the balance. How do you do it? Each unique solution will earn you 50 Protista Points! Winners:  Wiggum1006  le_battement Comment! (12)  Recommend! The 5 protistas on the run Friday, July 29, 2005 After crossing the bridge [refer to previous puzzle], the 4 hairy protistas meet up with their gangmate Mortopejia. Mortopejia has another flashlight and tells the others that there are 2 more (identical) bridges ahead. The sames rules as before [refer to previous puzzle] apply. It will take Mortopejia 7 seconds to cross a bridge. There is some ground between the 2 bridges, but the distance between the 2 bridges is insignificant compared to the lengths of the bridges. What is the shortest time it will take all 5 protistas to cross the 2 bridges ahead? Solved by Invisible for 25 Protista Points. Comment! (6)  Recommend! The 4 protistas on the run Friday, July 29, 2005 Well, well, well, it seems that my comeback puzzle took you all quite a long time. I am disappointed!! MUAHAhahahaa. So let's go back to nursery school with this next one. It's a classic. The gang of protistas is back, but only Omeali, Zygoe, Bengalii, and Yorz. In the dead of the night, these 4 have stolen some pennies and are on the run. To get home, they must cross a bridge that can only withstand the weight of 2 protistas at any time. As there is no moon out, they must cross with a flashlight. But, they only have 1 flashlight!! MUAhaHAHHAaa, foolish protistas. Omeali can cross the bridge in 1 second, Zygoe in 2 seconds, Bengalii in 5 seconds, and Yorz in 10 seconds. When two protistas cross the bridge, they cross at the speed of the slower one. What is the shortest time it will take all 4 protistas to cross the bridge? This time, your solution must include your logic. Solved by Le_battement for 20 Protista Points. Comment! (9)  Recommend! Shakeel's Fiendish Illusion Friday, July 22, 2005 Well, well, well, why am I not surprised this dumpster has attracted so many more nincompoops? I have been banished long enough, and I'm sure everyone has been awaiting my return. And what better time to return than now. And what better way to celebrate my return than with a logic puzzle. Let's see if you rodents have grown brains in my long absence. (I highly doubt it.) Long ago, there existed a beautiful place called the Kingdom of Liars and Logic Fiends. One logic fiend, Shakeel, wanted to perform a fiendish illusion to impress the king. To do this, he needed to create a perfectly square grid, with an even number of rows and columns. Each grid would be occupied by a liar or a logic fiend, such that each person can say "All my adjacent grids are occupied by people of the opposite persuasion." No, you dimwit, diagonal grids are not considered to be adjacent. (In other words, if you can't work out this simple math, there is a maximum of 4 adjacent grids.) Shakeel had a couple more requirements that needed to be fulfilled for his illusion to work: * there must be at least 100 participants * at least 37% of the participants must be logic fiends What is the mininum number of participants needed for Shakeel's fiendish illusion? Solved by Monkeymeister for 50 Protista Points. Comment! (8)  Recommend! 
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